1987

JEE Main 1987 Mathematics question on Limits Continuity and Differentiability

The set of all points, where the function f(x)=x1+∣x∣f(x) = \dfrac{x}{1+|x|} is differentiable, is
  1. A.
    (−∞,∞)(-\infty, \infty)
  2. B.
    [0,∞)[0, \infty)
  3. C.
    (−∞,0)∪(0,∞)(-\infty, 0) \cup (0, \infty)
  4. D.
    (0,∞)(0, \infty)
Show answer and solution

Correct option: A

Solution

For x > 0, f(x) = x/(1+x), and for x < 0, f(x) = x/(1-x), both rational functions differentiable on their domains. At x = 0, compute the limit: [f(h)-f(0)]/h = [h/(1+|h|)]/h = 1/(1+|h|) → 1 as h → 0 from either side. So f'(0) = 1 exists. Therefore f is differentiable on all of (-∞, ∞).

[1987]

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