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JEE Main 2019 · 12 Jan · Shift I

JEE Main 2019 Mathematics question on Binomial Theorem

The ratio of the 5th term from the beginning to the 5th term from the end in the binomial expansion of (213+12(3)13)10\left(2^{\frac{1}{3}} + \dfrac{1}{2(3)^{\frac{1}{3}}}\right)^{10} is
  1. A.
    1:2(6)131: 2(6)^{\frac{1}{3}}
  2. B.
    1:4(16)131: 4(16)^{\frac{1}{3}}
  3. C.
    4(36)13:14(36)^{\frac{1}{3}}: 1
  4. D.
    2(36)13:12(36)^{\frac{1}{3}}: 1
Show answer

Correct option: C

[JEE Main 2019 · 12 Jan · Shift I]

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