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JEE Main 2017

JEE Main 2017 Chemistry question on Atomic Structure

The radius of the second Bohr orbit for hydrogen atom is (Planck's constant (h)=6.6262×10−34(h) = 6.6262 \times 10^{-34} Js; mass of electron =9.1091×10−31= 9.1091 \times 10^{-31} kg; charge of electron (e)=1.60210×10−19(e) = 1.60210 \times 10^{-19} C; permittivity of vacuum (ε0)=8.854185×10−12kg−1m−3A2(\varepsilon_0) = 8.854185 \times 10^{-12} \text{kg}^{-1}\text{m}^{-3}\text{A}^2)
  1. A.
    1.65 Å
  2. B.
    4.76 Å
  3. C.
    0.529 Å
  4. D.
    2.12 Å
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Correct option: D

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