The probability that at least one of the events and occurs is 0.6. If and occur simultaneously with probability 0.2, then is equal to
- A.0.4
- B.0.8
- C.1.2
- D.1.4
Show answer and solution
Correct option: C
Solution
P(A∪B) = P(A) + P(B) - P(A∩B), so 0.6 = P(A) + P(B) - 0.2, giving P(A) + P(B) = 0.8. Then P(Ā) + P(B̄) = (1 - P(A)) + (1 - P(B)) = 2 - 0.8 = 1.2.
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