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JEE Main 2023 · 25 Jan · Shift 1

JEE Main 2023 Mathematics question on Definite Integrals and Areas

The minimum value of the function f(x)=∫02e∣x−t∣ dtf(x) = \int_{0}^{2} e^{|x-t|} \, dt is :
  1. A.
    2e−12e - 1
  2. B.
    22
  3. C.
    2(e−1)2(e - 1)
  4. D.
    e(e−1)e(e - 1)
Show answer

Correct option: C

[JEE Main 2023 · 25 Jan · Shift 1]

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