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JEE Main 1993 Mathematics question on Circles

The locus of the centre of a circle, which touches externally the circle x2+y2−6x−6y+14=0x^2 + y^2 - 6x - 6y + 14 = 0 and also touches the Y-axis, is given by the equation
  1. A.
    x2−6x−10y+14=0x^2 - 6x - 10y + 14 = 0
  2. B.
    x2−10x−6y+14=0x^2 - 10x - 6y + 14 = 0
  3. C.
    y2−6x−10y+14=0y^2 - 6x - 10y + 14 = 0
  4. D.
    y2−10x−6y+14=0y^2 - 10x - 6y + 14 = 0
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Correct option: D

[1993]

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