The incentre of the triangle with vertices , and is
- A.
- B.
- C.
- D.
Show answer and solution
Correct option: D
Solution
The triangle has vertices A=(1,√3), B=(0,0), C=(2,0). The side lengths are: a=BC=2, b=CA=√((1-2)²+(√3)²)=√(1+3)=2, c=AB=√(1+3)=2. So it's equilateral with all sides=2.
For an equilateral triangle, the incentre coincides with the centroid: ((1+0+2)/3, (√3+0+0)/3) = (1, √3/3) = (1, 1/√3).
For an equilateral triangle, the incentre coincides with the centroid: ((1+0+2)/3, (√3+0+0)/3) = (1, √3/3) = (1, 1/√3).
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