ExamHabit
Practise free

JEE Main 2014

JEE Main 2014 Mathematics question on Three Dimensional Geometry

The image of the line x−13=y−31=z−4−5\frac{x-1}{3} = \frac{y-3}{1} = \frac{z-4}{-5} in the plane 2x−y+z+3=02x - y + z + 3 = 0 is the line
  1. A.
    x+33=y−51=z−2−5\frac{x+3}{3} = \frac{y-5}{1} = \frac{z-2}{-5}
  2. B.
    x+3−3=y−5−1=z+25\frac{x+3}{-3} = \frac{y-5}{-1} = \frac{z+2}{5}
  3. C.
    x−33=y+51=z−2−5\frac{x-3}{3} = \frac{y+5}{1} = \frac{z-2}{-5}
  4. D.
    x−3−3=y+5−1=z−25\frac{x-3}{-3} = \frac{y+5}{-1} = \frac{z-2}{5}
Show answer

Correct option: A

[JEE Main 2014]

Practise Three Dimensional Geometry the way it is asked

A timed set of real JEE Main Three Dimensional Geometry questions, graded as the exam grades. No sign-up.

Start a Three Dimensional Geometry test

More: all JEE Main Three Dimensional Geometry questions · JEE Main 2014 · Mathematics chapter list