JEE Main 2023 · 24 Jan · Shift 2

JEE Main 2023 Physics question on Electromagnetic Waves

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

Ex=E0sin⁡(kz−ωt)E_x = E_0 \sin(kz - \omega t)

By=B0sin⁡(kz−ωt)B_y = B_0 \sin(kz - \omega t)

Then the correct relation between E0E_0 and B0B_0 is given by
  1. A.
    E0=kB0E_0 = kB_0
  2. B.
    E0B0=ωkE_0 B_0 = \omega k
  3. C.
    ωE0=kB0\omega E_0 = kB_0
  4. D.
    kE0=ωB0kE_0 = \omega B_0
Show answer and solution

Correct option: D

Solution

From Maxwell's equations, the relation between E and B in an EM wave comes from Faraday's law: ∂Ex/∂z = -∂By/∂t. Differentiating: kE₀cos(kz-ωt) = ωB₀cos(kz-ωt), giving kE₀ = ωB₀. This is consistent with the fact that E₀/B₀ = ω/k = c (speed of light in vacuum).

[JEE Main 2023 · 24 Jan · Shift 2]

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