JEE Main 2019 · 9 Apr · Shift II

JEE Main 2019 Mathematics question on Circles

The common tangent to the circles x2+y2=4x^2 + y^2 = 4 and x2+y2+6x+8y−24=0x^2 + y^2 + 6x + 8y - 24 = 0 also passes through the point
  1. A.
    (6, -2)
  2. B.
    (4, -2)
  3. C.
    (-6, 4)
  4. D.
    (-4, 6)
Show answer

Correct option: A

[JEE Main 2019 · 9 Apr · Shift II]

Practise Circles the way it is asked

A timed set of real JEE Main Circles questions, graded as the exam grades. No sign-up.

Start a Circles test

More: all JEE Main Circles questions · JEE Main 2019 · Mathematics chapter list