JEE Main 2019 · 8 Apr · Shift I

JEE Main 2019 Physics question on Electrostatics

The bob of a simple pendulum has mass 2g and a charge of 5.0μC. It is at rest in a uniform horizontal electric field of intensity 2000 V/m. At equilibrium, the angle that the pendulum makes with the vertical is (take g=10 m/s2g = 10 \text{ m/s}^2)
  1. A.
    tan⁡−1(2.0)\tan^{-1}(2.0)
  2. B.
    tan⁡−1(0.2)\tan^{-1}(0.2)
  3. C.
    tan⁡−1(5.0)\tan^{-1}(5.0)
  4. D.
    tan⁡−1(0.5)\tan^{-1}(0.5)
Show answer

Correct option: D

[JEE Main 2019 · 8 Apr · Shift I]

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