ExamHabit
Practise free

AIEEE 2004

JEE Main 2004 Mathematics question on Definite Integrals and Areas

The area enclosed between the curves y=ax2y = ax^2 and x=ay2x = ay^2 (a>0)(a > 0) is 1 sq unit. Then, the value of aa is
  1. A.
    13\dfrac{1}{\sqrt{3}}
  2. B.
    12\dfrac{1}{2}
  3. C.
    11
  4. D.
    13\dfrac{1}{3}
Show answer

Correct option: A

[AIEEE 2004]

Practise Definite Integrals and Areas the way it is asked

A timed set of real JEE Main Definite Integrals and Areas questions, graded as the exam grades. No sign-up.

Start a Definite Integrals and Areas test

More: all JEE Main Definite Integrals and Areas questions · JEE Main 2004 · Mathematics chapter list