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JEE Main 2019 · 12 Apr · Shift II

JEE Main 2019 Mathematics question on Trigonometry

The angle of elevation of the top of a vertical tower standing on a horizontal plane is observed to be 45° from a point AA on the plane. Let BB be the point 30 m vertically above the point AA. If the angle of elevation of the top of the tower from BB be 30°, then the distance (in m) of the foot of the tower from the point AA is
  1. A.
    15(3+3)15(3 + \sqrt{3})
  2. B.
    15(5−3)15(5 - \sqrt{3})
  3. C.
    15(3−3)15(3 - \sqrt{3})
  4. D.
    15(1+3)15(1 + \sqrt{3})
Show answer

Correct option: A

[JEE Main 2019 · 12 Apr · Shift II]

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