JEE Main 2023 · 29 Jan · Shift 1 · numerical answer

JEE Main 2023 Chemistry question on Solutions

Solid Lead nitrate is dissolved in 1 litre of water. The solution was found to boil at 100.15° C. When 0.2 mol of NaCl is added to the resulting solution, it was observed that the solution froze at -0.8° C. The solubility product of PbCl2\text{PbCl}_2 formed is _________ ×10−x\times 10^{-x} at 298 K. (Nearest integer)

Given : Kb=0.5K_b = 0.5 K kg mol−1^{-1} and Kf=1.8K_f = 1.8 K kg mol−1^{-1}. Assume molality to be equal to molarity in all cases.
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Answer: 13

[JEE Main 2023 · 29 Jan · Shift 1]

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