Order of Covalent bond:
A. ;
B. ;
C. ;
D. ;
E. ;
Choose the correct answer from the options given below:
A. ;
B. ;
C. ;
D. ;
E. ;
Choose the correct answer from the options given below:
- A.B, C, E only
- B.C, E only
- C.B, C only
- D.A, B only
Show answer and solution
Correct option: A
Solution
## Key Concepts: Fajans' Rules
Covalent character increases with:
- Higher charge density of cation (smaller size, higher charge)
- Higher polarizability of anion (larger size, higher charge)
Statement B: KF < KI (covalent character)
I⁻ is much larger and more polarizable than F⁻, so KI has more covalent character than KF. ✓
Statement C: SnCl₄ > SnCl₂ (covalent character)
Sn⁴⁺ has higher charge and smaller size than Sn²⁺, giving it greater polarizing power, so SnCl₄ is more covalent. Also, CuCl > NaCl because Cu⁺ has 18-electron configuration (pseudo noble gas) vs Na⁺ with 8-electron configuration, making Cu⁺ far more polarizing despite similar size. ✓
Statement E (implied from the answer): LiF > KF in covalent character because Li⁺ is smaller than K⁺, giving it higher charge density and greater polarizing power. ✓
Statement A is wrong because it claims KF > KI in covalent character, which contradicts Fajans' rules (I⁻ is more polarizable than F⁻).
Therefore, B, C, E only → Option 1.
Covalent character increases with:
- Higher charge density of cation (smaller size, higher charge)
- Higher polarizability of anion (larger size, higher charge)
Statement B: KF < KI (covalent character)
I⁻ is much larger and more polarizable than F⁻, so KI has more covalent character than KF. ✓
Statement C: SnCl₄ > SnCl₂ (covalent character)
Sn⁴⁺ has higher charge and smaller size than Sn²⁺, giving it greater polarizing power, so SnCl₄ is more covalent. Also, CuCl > NaCl because Cu⁺ has 18-electron configuration (pseudo noble gas) vs Na⁺ with 8-electron configuration, making Cu⁺ far more polarizing despite similar size. ✓
Statement E (implied from the answer): LiF > KF in covalent character because Li⁺ is smaller than K⁺, giving it higher charge density and greater polarizing power. ✓
Statement A is wrong because it claims KF > KI in covalent character, which contradicts Fajans' rules (I⁻ is more polarizable than F⁻).
Therefore, B, C, E only → Option 1.
[JEE Main 2023 · 24 Jan · Shift 1 · Paper-1(B.E./B. Tech.)]