JEE Main 2023 · 29 Jan · Shift 1 · numerical answer

JEE Main 2023 Chemistry question on Equilibrium

Millimoles of calcium hydroxide required to produce 100 mL of the aqueous solution of pH 12 is x×10−1x \times 10^{-1}. The value of xx is _________ (Nearest integer).

Assume complete dissociation.
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Answer: 05

Solution

pH = 12 → pOH = 2 → [OH⁻] = 10⁻² M

Moles of OH⁻ needed = 10⁻² × 0.1 L = 10⁻³ mol = 1 mmol

Ca(OH)₂ → Ca²⁺ + 2OH⁻, so mmol of Ca(OH)₂ = 1/2 = 0.5 mmol = 5 × 10⁻¹ mmol

Therefore x = 5.

[JEE Main 2023 · 29 Jan · Shift 1]

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