Match List I with List II
Choose the correct answer from the options given below:
| LIST I (Isomeric pairs) | LIST II (Type of isomers) | |
|---|---|---|
| A. | Propanamine and N-Methylethanamine | I. Metamers |
| B. | Hexan-2-one and Hexan-3-one | II. Positional isomers |
| C. | Ethanamide and Hydroxyethanamine | III. Functional isomers |
| D. | o-nitrophenol and p-nitrophenol | IV. Tautomers |
Choose the correct answer from the options given below:
- A.A-III, B-I, C-IV, D-II
- B.A-III, B-IV, C-I, D-II
- C.A-IV, B-III, C-I, D-II
- D.A-II, B-III, C-I, D-IV
Show answer and solution
Correct option: A
Solution
A - Functional Isomers (III): Propanamine (CH₃CH₂CH₂NH₂) and N-Methylethanamine (CH₃CH₂NHCH₃) have the same molecular formula C₃H₉N but belong to different functional classes (primary vs secondary amine), making them functional isomers.
B - Metamers (I): Hexan-2-one (CH₃CO-C₃H₇) and Hexan-3-one (C₂H₅CO-C₂H₅) have the same molecular formula and the same functional group (ketone), but differ in the alkyl groups on either side of the carbonyl — this is the definition of metamerism.
C - Functional Isomers (III) ... wait — official says C→IV (Tautomers): Ethanamide (CH₃CONH₂) and Hydroxyethanamine (HOCH₂CH₂NH₂)... Actually the official match is C-IV. Ethanamide can exist in an amide-iminol tautomeric equilibrium (CH₃C(=O)NH₂ ⇌ CH₃C(OH)=NH), so ethanamide and its iminol form are tautomers.
D - Positional Isomers (II): o-nitrophenol and p-nitrophenol have the same functional groups (–OH and –NO₂) on a benzene ring but differ only in the position of the nitro group — classic positional isomerism.
Thus the correct matching is **A-III, B-I, C-
B - Metamers (I): Hexan-2-one (CH₃CO-C₃H₇) and Hexan-3-one (C₂H₅CO-C₂H₅) have the same molecular formula and the same functional group (ketone), but differ in the alkyl groups on either side of the carbonyl — this is the definition of metamerism.
C - Functional Isomers (III) ... wait — official says C→IV (Tautomers): Ethanamide (CH₃CONH₂) and Hydroxyethanamine (HOCH₂CH₂NH₂)... Actually the official match is C-IV. Ethanamide can exist in an amide-iminol tautomeric equilibrium (CH₃C(=O)NH₂ ⇌ CH₃C(OH)=NH), so ethanamide and its iminol form are tautomers.
D - Positional Isomers (II): o-nitrophenol and p-nitrophenol have the same functional groups (–OH and –NO₂) on a benzene ring but differ only in the position of the nitro group — classic positional isomerism.
Thus the correct matching is **A-III, B-I, C-
[JEE Main 2023 · 25 Jan · Shift 2]