JEE Main 2023 · 25 Jan · Shift 2

JEE Main 2023 Chemistry question on Coordination Compounds

Match List I with List II

LIST ILIST II
Coordination entityWavelength of light absorbed in nm
A. [CoCl(NH3)5]2+[\text{CoCl(NH}_3)_5]^{2+}I. 310
B. [Co(NH3)6]3+[\text{Co(NH}_3)_6]^{3+}II. 475
C. [Co(CN)6]3−[\text{Co(CN)}_6]^{3-}III. 535
D. [Cu(H2O)4]2+[\text{Cu(H}_2\text{O)}_4]^{2+}IV. 600


Choose the correct answer from the options given below:
  1. A.
    A-II, B-III, C-IV, D-I
  2. B.
    A-IV, B-I, C-III, D-II
  3. C.
    A-III, B-I, C-II, D-IV
  4. D.
    A-III, B-II, C-I, D-IV
Show answer and solution

Correct option: D

Solution

The spectrochemical series gives field strength order: CN⁻ > NH₃ > Cl⁻, and Cu²⁺ (d⁹) complexes absorb at much longer wavelengths (lower energy) than Co³⁺ (d⁶) complexes.

For the Co³⁺ complexes, stronger field ligands produce larger Δo, meaning higher energy (shorter wavelength) light is absorbed:
- [Co(CN)₆]³⁻: strongest field → highest Δo → absorbs at 310 nm (UV, C-I)
- [Co(NH₃)₆]³⁺: intermediate field → absorbs at 475 nm (B-II)
- [CoCl(NH₃)₅]²⁺: Cl⁻ weakens the field slightly vs pure NH₃ → absorbs at 535 nm (A-III)
- [Cu(H₂O)₄]²⁺: d⁹ Cu²⁺ with weak field water ligands → smallest Δo → absorbs at 600 nm (D-IV)

This gives A-III, B-II, C-I, D-IV, which is option 4.

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