JEE Main 2023 · 25 Jan · Shift 1

JEE Main 2023 Physics question on Units and Measurements

Match List I with List II

List I (Current configuration)List II (Magnitude of Magnetic Field at point O)
A. [straight wire with circular loop of radius r at center, current I]I. B0=μ0I4πr[π+2]B_0 = \dfrac{\mu_0 I}{4\pi r}[\pi + 2]
B. [semicircular loop of radius r with two parallel straight wires, current I]II. B0=μ04IrB_0 = \dfrac{\mu_0}{4} \dfrac{I}{r}
C. [three-quarter circular arc of radius r with two straight wires, current I]III. B0=μ0I2πr[π−1]B_0 = \dfrac{\mu_0 I}{2\pi r}[\pi - 1]
D. [straight wire with semicircular dip of radius r below, current I]IV. B0=μ0I4πr[π+1]B_0 = \dfrac{\mu_0 I}{4\pi r}[\pi + 1]


Choose the correct answer from the options given below :

  1. A.
    A–I, B–III, C–IV, D–II
  2. B.
    A–III, B–IV, C–I, D–II
  3. C.
    A–III, B–I, C–IV, D–II
  4. D.
    A–II, B–I, C–IV, D–III
Show answer

Correct option: C

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