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JEE Main 2019 · 9 Jan · Shift I

JEE Main 2019 Mathematics question on Limits Continuity and Differentiability

lim⁡y→01+1+y4−2y4\lim_{y \to 0} \dfrac{\sqrt{1 + \sqrt{1 + y^4}} - \sqrt{2}}{y^4} \hspace{2cm}
  1. A.
    exists and equals 142\dfrac{1}{4\sqrt{2}}
  2. B.
    does not exist
  3. C.
    exists and equals 122\dfrac{1}{2\sqrt{2}}
  4. D.
    exists and equals 122(2+1)\dfrac{1}{2\sqrt{2}(\sqrt{2}+1)}
Show answer

Correct option: A

[JEE Main 2019 · 9 Jan · Shift I]

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