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JEE Main Mathematics question on Limits Continuity and Differentiability lim n → ∞ 1 n ∑ r = 1 2 n r n 2 + r 2 \lim_{n \to \infty} \frac{1}{n} \sum_{r=1}^{2n} \frac{r}{\sqrt{n^2 + r^2}} lim n → ∞ n 1 ∑ r = 1 2 n n 2 + r 2 r equals
A. B. C. D. Show answer and solution Correct option: B
Solution
Convert to a Riemann sum by writing r/n = x and 1/n as dx. The sum becomes the integral from 0 to 2 of x/√(1+x²) dx (since r goes from 1 to 2n, r/n goes from 0 to 2). Evaluating: ∫₀² x/√(1+x²) dx = [√(1+x²)]₀² = √5 - √1 = √5 - 1.
Previous-year question, JEE Main.
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