AIEEE 2012

JEE Main 2012 Mathematics question on Complex Numbers and Quadratic Equations

Let zz be a complex number such that the imaginary part of zz is non-zero and a=z2+z+1a = z^2 + z + 1 is real. Then, aa cannot take the value
  1. A.
    −1-1
  2. B.
    13\frac{1}{3}
  3. C.
    12\frac{1}{2}
  4. D.
    34\frac{3}{4}
Show answer and solution

Correct option: D

Solution

Let z = x + iy with y ≠ 0. Since a = z² + z + 1 is real, its imaginary part must be zero.

Im(z² + z + 1) = Im(x² - y² + 2xyi + x + iy + 1) = 2xy + y = y(2x + 1) = 0.

Since y ≠ 0, we need 2x + 1 = 0, so x = -1/2.

Now compute the real part: a = x² - y² + x + 1 = 1/4 - y² - 1/2 + 1 = 3/4 - y².

Since y ≠ 0, we have y² > 0, so a = 3/4 - y² < 3/4.

Therefore a can take any value less than 3/4, but cannot equal 3/4.

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