Let and . The set represents a
- A.straight line with the sum of its intercepts on the coordinate axes equals 14
- B.straight line with the sum of its intercepts on the coordinate axes equals
- C.hyperbola with eccentricity 2
- D.hyperbola with the length of the transverse axis 7
Show answer and solution
Correct option: A
Solution
Let z = x + iy. Then:
|z - z₁|² = (x-2)² + (y-3)²
|z - z₂|² = (x-3)² + (y-4)²
|z₁ - z₂|² = 1 + 1 = 2
Expanding the condition:
(x-2)² + (y-3)² - (x-3)² - (y-4)² = 2
(x²-4x+4) - (x²-6x+9) + (y²-6y+9) - (y²-8y+16) = 2
2x - 5 + 2y - 7 = 2
2x + 2y = 14
x + y = 7
This is a straight line. The x-intercept is 7 (set y=0) and y-intercept is 7 (set x=0), so the sum of intercepts = 7 + 7 = 14.
|z - z₁|² = (x-2)² + (y-3)²
|z - z₂|² = (x-3)² + (y-4)²
|z₁ - z₂|² = 1 + 1 = 2
Expanding the condition:
(x-2)² + (y-3)² - (x-3)² - (y-4)² = 2
(x²-4x+4) - (x²-6x+9) + (y²-6y+9) - (y²-8y+16) = 2
2x - 5 + 2y - 7 = 2
2x + 2y = 14
x + y = 7
This is a straight line. The x-intercept is 7 (set y=0) and y-intercept is 7 (set x=0), so the sum of intercepts = 7 + 7 = 14.
[JEE Main 2023 · 25 Jan · Shift 1]