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JEE Main 2023 · 24 Jan · Shift 2

JEE Main 2023 Mathematics question on Differential Equations

Let y=y(x)y = y(x) be the solution of the differential equation (x2−3y2) dx+3xy dy=0, y(1)=1(x^2 - 3y^2)\,dx + 3xy\,dy = 0,\, y(1) = 1.

Then 6y2(e)6y^2(e) is equal to
  1. A.
    32e2\dfrac{3}{2}e^2
  2. B.
    e2e^2
  3. C.
    2e22e^2
  4. D.
    3e23e^2
Show answer

Correct option: C

[JEE Main 2023 · 24 Jan · Shift 2]

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