JEE Main 2019 · 11 Jan · Shift II
JEE Main 2019 Mathematics question on Binomial Theorem
Let
(x+10)50+(x−10)50=a0+a1x+a2x2+…+a50x50 for all
x∈R; then
a0a2 is equal to
- A.
12.25
- B.
12.50
- C.
12.00
- D.
12.75
Show answer
Correct option: A
[JEE Main 2019 · 11 Jan · Shift II]
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