JEE Main 2023 · 25 Jan · Shift 2

JEE Main 2023 Mathematics question on Application of Derivatives

Let the function f(x)=2x3+(2p−7)x2+3(2p−9)x−6f(x) = 2x^3 + (2p-7)x^2 + 3(2p-9)x - 6 have a maxima for some value of x<0x < 0 and a minima for some value of x>0x > 0. Then, the set of all values of pp is
  1. A.
    (−92,92)\left(-\dfrac{9}{2}, \dfrac{9}{2}\right)
  2. B.
    (0,92)\left(0, \dfrac{9}{2}\right)
  3. C.
    (−∞,92)\left(-\infty, \dfrac{9}{2}\right)
  4. D.
    (92,∞)\left(\dfrac{9}{2}, \infty\right)
Show answer

Correct option: C

[JEE Main 2023 · 25 Jan · Shift 2]

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