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JEE Main 2019 · 9 Jan · Shift II

JEE Main 2019 Mathematics question on Straight Lines and Pair of Lines

Let the equations of two sides of a triangle be 3x−2y+6=03x - 2y + 6 = 0 and 4x+5y−20=04x + 5y - 20 = 0. If the orthocentre of this triangle is at (1,1)(1, 1) then the equation of its third side is
  1. A.
    122y−26x−1675=0122y - 26x - 1675 = 0
  2. B.
    26x−122y−1675=026x - 122y - 1675 = 0
  3. C.
    122y+26x+1675=0122y + 26x + 1675 = 0
  4. D.
    26x+61y+1675=026x + 61y + 1675 = 0
Show answer

Correct option: B

[JEE Main 2019 · 9 Jan · Shift II]

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