JEE Main 2023 · 25 Jan · Shift 1 · numerical answer

JEE Main 2023 Mathematics question on Three Dimensional Geometry

Let the equation of the plane passing through the line x−2y−z−5=0=x+y+3z−5x - 2y - z - 5 = 0 = x + y + 3z - 5 and parallel to the line x+y+2z−7=0=2x+3y+z−2x + y + 2z - 7 = 0 = 2x + 3y + z - 2 be ax+by+cz=65ax + by + cz = 65. Then the distance of the point (a,b,c)(a, b, c) from the plane 2x+2y−z+16=02x + 2y - z + 16 = 0 is
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Answer: 9

[JEE Main 2023 · 25 Jan · Shift 1]

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