JEE Main 2018

JEE Main 2018 Mathematics question on Limits Continuity and Differentiability

Let S={t∈R:f(x)=∣x−π∣⋅(e∣x∣−1)sin⁡∣x∣}S = \{t \in \mathbb{R} : f(x) = |x - \pi| \cdot (e^{|x|} - 1)\sin|x|\} is not differentiable at tt. Then, the set SS is equal to
  1. A.
    ϕ\phi (an empty set)
  2. B.
    {0}\{0\}
  3. C.
    {π}\{\pi\}
  4. D.
    {0,π}\{0, \pi\}
Show answer

Correct option: A

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