JEE Main 2019 · 9 April · Shift I

JEE Main 2019 Mathematics question on Trigonometry

Let S={θ∈[−2π,2π]:2cos⁡2θ+3sin⁡θ=0}S = \{\theta \in [-2\pi, 2\pi] : 2\cos^2\theta + 3\sin\theta = 0\}, then the sum of the elements of SS is
  1. A.
    2π2\pi
  2. B.
    π\pi
  3. C.
    5π3\dfrac{5\pi}{3}
  4. D.
    13π6\dfrac{13\pi}{6}
Show answer

Correct option: A

[JEE Main 2019 · 9 April · Shift I]

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