JEE Main 2019 · 12 Jan · Shift I

JEE Main 2019 Mathematics question on Conic Sections

Let P(4,−4)P(4, -4) and Q(9,6)Q(9, 6) be two points on the parabola, y2=4xy^2 = 4x and let XX be any point on the arc POQPOQ of this parabola, where OO is the vertex of this parabola, such that the area of △PXQ\triangle PXQ is maximum. Then, this maximum area (in sq units) is
  1. A.
    1252\dfrac{125}{2}
  2. B.
    752\dfrac{75}{2}
  3. C.
    6254\dfrac{625}{4}
  4. D.
    1254\dfrac{125}{4}
Show answer

Correct option: D

[JEE Main 2019 · 12 Jan · Shift I]

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