JEE Main 2015

JEE Main 2015 Mathematics question on Conic Sections

Let OO be the vertex and QQ be any point on the parabola x2=8yx^2 = 8y. If the point PP divides the line segment OQOQ internally in the ratio 1:31:3, then the locus of PP is
  1. A.
    x2=yx^2 = y
  2. B.
    y2=xy^2 = x
  3. C.
    y2=2xy^2 = 2x
  4. D.
    x2=2yx^2 = 2y
Show answer and solution

Correct option: D

Solution

Q is on x²=8y, so parametrize Q as (4t, 2t²). O is (0,0). P divides OQ in ratio 1:3, so P = (1·Q + 3·O)/(1+3) = (4t/4, 2t²/4) = (t, t²/2). Let P=(h,k): h=t, k=t²/2, so k=h²/2, giving h²=2k. The locus is x²=2y.

[JEE Main 2015]

Practise Conic Sections the way it is asked

A timed set of real JEE Main Conic Sections questions, graded as the exam grades. No sign-up.

Start a Conic Sections test

More: all JEE Main Conic Sections questions · JEE Main 2015 · Mathematics chapter list