Let . If , where is a constant of integration, then the ordered pair is equal to
- A.
- B.
- C.
- D.
Show answer and solution
Correct option: B
Solution
Using the reduction identity: In + I_(n+2) = tan^(n+1)(x)/(n+1).
So I4 + I6 = tan5(x)/5 + C.
Comparing with a·tan5(x) + b·x5 + C gives a = 1/5 and b = 0.
So I4 + I6 = tan5(x)/5 + C.
Comparing with a·tan5(x) + b·x5 + C gives a = 1/5 and b = 0.
[JEE Main 2017]