Let be a differentiable function from to such that , for all . If , then is equal to
- A.2
- B.
- C.1
- D.0
Show answer and solution
Correct option: C
Solution
From the condition, |f(x) - f(y)| ≤ 2|x - y|^(3/2). Dividing both sides by |x - y| and taking the limit as y → x gives |f'(x)| ≤ 2|x - y|^(1/2) → 0, so f'(x) = 0 for all x. Thus f is a constant function, and since f(0) = 1, f(x) = 1 everywhere. Therefore ∫₀¹ f²(x) dx = ∫₀¹ 1 dx = 1.
[JEE Main 2019 · 9 Jan · Shift II]