Let denotes the complement of an event . If , , are pairwise independent events with and . Then, equals
- A.
- B.
- C.
- D.
Show answer and solution
Correct option: C
Solution
P(Eᶜ ∩ Fᶜ | G) = P(Eᶜ ∩ Fᶜ ∩ G) / P(G).
Now P(Eᶜ ∩ Fᶜ ∩ G) = P(G) - P(E ∩ G) - P(F ∩ G) + P(E ∩ F ∩ G).
Since E,F,G are pairwise independent: P(E ∩ G) = P(E)P(G) and P(F ∩ G) = P(F)P(G), and P(E ∩ F ∩ G) = 0.
So P(Eᶜ ∩ Fᶜ | G) = [P(G) - P(E)P(G) - P(F)P(G)] / P(G) = 1 - P(E) - P(F) = P(Eᶜ) - P(F), which is option 3.
Now P(Eᶜ ∩ Fᶜ ∩ G) = P(G) - P(E ∩ G) - P(F ∩ G) + P(E ∩ F ∩ G).
Since E,F,G are pairwise independent: P(E ∩ G) = P(E)P(G) and P(F ∩ G) = P(F)P(G), and P(E ∩ F ∩ G) = 0.
So P(Eᶜ ∩ Fᶜ | G) = [P(G) - P(E)P(G) - P(F)P(G)] / P(G) = 1 - P(E) - P(F) = P(Eᶜ) - P(F), which is option 3.
[AIEEE 2007]