1992

JEE Main 1992 Mathematics question on Complex Numbers and Quadratic Equations

Let α,β\alpha, \beta be the roots of the equation, (x−a)(x−b)=c,c≠0(x-a)(x-b) = c, c \neq 0. Then the roots of the equation (x−α)(x−β)+c=0(x-\alpha)(x-\beta) + c = 0 are
  1. A.
    a,ca, c
  2. B.
    b,cb, c
  3. C.
    c,a,bc, a, b
  4. D.
    a+c,b+ca + c, b + c
Show answer

Correct option: C

[1992]

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