AIEEE 2010

JEE Main 2010 Mathematics question on Probability

Let ω\omega be a complex cube root of unity with ω≠1\omega \neq 1. A fair die is thrown three times. If r1r_1, r2r_2 and r3r_3 are the numbers obtained on the die, then the probability that ωr1+ωr2+ωr3=0\omega^{r_1} + \omega^{r_2} + \omega^{r_3} = 0, is
  1. A.
    1/18
  2. B.
    1/9
  3. C.
    2/9
  4. D.
    1/36
Show answer

Correct option: C

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