JEE Main 2023 · 29 Jan · Shift 1

JEE Main 2023 Mathematics question on Definite Integrals and Areas

Let A={(x,y)∈R2:y≥0,2x≤y≤4−(x−1)2}A = \{(x, y) \in \mathbb{R}^2 : y \geq 0, 2x \leq y \leq \sqrt{4-(x-1)^2}\} and B={(x,y)∈R×R:0≤y≤min⁡{2x,4−(x−1)2}}B = \{(x, y) \in \mathbb{R} \times \mathbb{R} : 0 \leq y \leq \min\left\{2x, \sqrt{4-(x-1)^2}\right\}\}. Then the ratio of the area of AA to the area of BB is
  1. A.
    π−1π+1\dfrac{\pi - 1}{\pi + 1}
  2. B.
    ππ−1\dfrac{\pi}{\pi - 1}
  3. C.
    π+1π−1\dfrac{\pi + 1}{\pi - 1}
  4. D.
    ππ+1\dfrac{\pi}{\pi + 1}
Show answer

Correct option: A

[JEE Main 2023 · 29 Jan · Shift 1]

Practise Definite Integrals and Areas the way it is asked

A timed set of real JEE Main Definite Integrals and Areas questions, graded as the exam grades. No sign-up.

Start a Definite Integrals and Areas test

More: all JEE Main Definite Integrals and Areas questions · JEE Main 2023 · Mathematics chapter list