JEE Main 2019 · 11 Jan · Shift I

JEE Main 2019 Mathematics question on Vector Algebra

Let a⃗=i^+2j^+4k^\vec{a} = \hat{i} + 2\hat{j} + 4\hat{k}, b⃗=i^+λj^+4k^\vec{b} = \hat{i} + \lambda\hat{j} + 4\hat{k} and c⃗=2i^+4j^+(λ2−1)k^\vec{c} = 2\hat{i} + 4\hat{j} + (\lambda^2 - 1)\hat{k} be coplanar vectors. Then, the non-zero vector a⃗×c⃗\vec{a} \times \vec{c} is
  1. A.
    −10i^+5j^-10\hat{i} + 5\hat{j}
  2. B.
    −10i^−5j^-10\hat{i} - 5\hat{j}
  3. C.
    −14i^−5j^-14\hat{i} - 5\hat{j}
  4. D.
    −14i^+5j^-14\hat{i} + 5\hat{j}
Show answer

Correct option: A

[JEE Main 2019 · 11 Jan · Shift I]

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