JEE Main 2018

JEE Main 2018 Mathematics question on Sequences and Series

Let AA be the sum of the first 20 terms and BB be the sum of the first 40 terms of the series
12+2⋅22+32+2⋅42+52+2⋅62+…1^2 + 2 \cdot 2^2 + 3^2 + 2 \cdot 4^2 + 5^2 + 2 \cdot 6^2 + \ldots
If B−2A=100λB - 2A = 100\lambda, then λ\lambda is equal to
  1. A.
    232
  2. B.
    248
  3. C.
    464
  4. D.
    496
Show answer

Correct option: B

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