JEE Main 2019 · 9 April · Shift I
JEE Main 2019 Mathematics question on Vector Algebra
Let
α=3i^+j^ and
β=2i^−j^+3k^. If
β=β1−β2, where
β1 is parallel to
α and
β2 is perpendicular to
α, then
β1×β2 is equal to
- A.
21(3i^−9j^+5k^) - B.
21(−3i^+9j^+5k^) - C.
−3i^+9j^+5k^ - D.
3i^−9j^−5k^
Show answer
Correct option: C
[JEE Main 2019 · 9 April · Shift I]
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