JEE Main 2023 · 24 Jan · Shift 2

JEE Main 2023 Physics question on Thermodynamics

In an Isothermal change, the change in pressure and volume of a gas can be represented for three different temperature; T3>T2>T1T_3 > T_2 > T_1 as :
  1. A.
  2. B.
  3. C.
  4. D.
Show answer and solution

Correct option: C

Solution

For an isothermal process, PV = nRT = constant, so the P-V curves are rectangular hyperbolas. The key features to identify the correct graph:

1. Higher temperature → higher PV product → the hyperbola for T₃ (highest) lies furthest from the origin, T₁ (lowest) lies closest to the origin.

2. Shape: Each curve must be a rectangular hyperbola (P = nRT/V), curving away from both axes, never touching them.

In option 3, the three isotherms are correctly drawn as rectangular hyperbolas with T₃ > T₂ > T₁ ordering from outermost to innermost — higher temperature isotherms lie farther from the origin since at any given volume, higher T means higher pressure (P = nRT/V).

[JEE Main 2023 · 24 Jan · Shift 2]

Practise Thermodynamics the way it is asked

A timed set of real JEE Main Thermodynamics questions, graded as the exam grades. No sign-up.

Start a Thermodynamics test

More: all JEE Main Thermodynamics questions · JEE Main 2023 · Physics chapter list