If z = dfrac√(3)2 + i/2 (i = √(-1) ), then (1 + iz + z^5 + iz^8)^9 is equal to

If z = dfrac√(3)2 + i/2 (i = √(-1) ), then (1 + iz + z^5 +… — JEE Main 2019 Mathematics PYQ

JEE Main 2019 · 8 April · Shift II

z = \dfrac{\sqrt{3}}{2} + \dfrac{i}{2}

\left(i = \sqrt{-1}\right)

, then

(1 + iz + z^5 + iz^8)^9

is equal to

Show answer

Correct option: C

[JEE Main 2019 · 8 April · Shift II]

Practise Complex Numbers and Quadratic Equations the way it is asked

A timed set of real JEE Main Complex Numbers and Quadratic Equations questions, graded as the exam grades. No sign-up.