AIEEE 2004

JEE Main 2004 Mathematics question on Differential Equations

If y=y(x)y = y(x) and 2+sin⁡xy+1(dydx)=−cos⁡x\dfrac{2 + \sin x}{y + 1} \left(\dfrac{dy}{dx}\right) = -\cos x, y(0)=1y(0) = 1, then y(π2)y\left(\dfrac{\pi}{2}\right) equals
  1. A.
    1/31/3
  2. B.
    2/32/3
  3. C.
    −1/3-1/3
  4. D.
    11
Show answer and solution

Correct option: A

Solution

Separate variables: dy/(y+1) = -cos x dx/(2+sin x).

Integrate both sides: ln|y+1| = -ln|2+sin x| + C, so (y+1)(2+sin x) = K.

Apply y(0)=1: (1+1)(2+0) = K → K = 4.

At x=π/2: (y+1)(2+1) = 4 → y+1 = 4/3 → y = 1/3.

[AIEEE 2004]

Practise Differential Equations the way it is asked

A timed set of real JEE Main Differential Equations questions, graded as the exam grades. No sign-up.

Start a Differential Equations test

More: all JEE Main Differential Equations questions · JEE Main 2004 · Mathematics chapter list