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JEE Main 2019 · 10 Apr · Shift II

JEE Main 2019 Mathematics question on Indefinite Integration

If ∫x2e−x2dx=g(x)e−x2+C\int x^2 e^{-x^2} dx = g(x)e^{-x^2} + C, where CC is a constant of integration, then g(−1)g(-1) is equal to
  1. A.
    −1-1
  2. B.
    11
  3. C.
    −12-\dfrac{1}{2}
  4. D.
    −52-\dfrac{5}{2}
Show answer

Correct option: D

[JEE Main 2019 · 10 Apr · Shift II]

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