ExamHabit
Practise free

JEE Main 2019 · 10 Jan · Shift I

JEE Main 2019 Mathematics question on Binomial Theorem

If the third term in the binomial expansion of (1+xlog⁡2x)5(1 + x^{\log_2 x})^5 equals 2560, then a possible value of xx is
  1. A.
    424\sqrt{2}
  2. B.
    14\dfrac{1}{4}
  3. C.
    18\dfrac{1}{8}
  4. D.
    222\sqrt{2}
Show answer

Correct option: B

[JEE Main 2019 · 10 Jan · Shift I]

Practise Binomial Theorem the way it is asked

A timed set of real JEE Main Binomial Theorem questions, graded as the exam grades. No sign-up.

Start a Binomial Theorem test

More: all JEE Main Binomial Theorem questions · JEE Main 2019 · Mathematics chapter list