JEE Main 2019 · 9 April · Shift II

JEE Main 2019 Mathematics question on Conic Sections

If the tangent to the parabola y2=xy^2 = x at a point (α,β)(\alpha, \beta), (β>0)(\beta > 0) is also a tangent to the ellipse x2+2y2=1x^2 + 2y^2 = 1, then α\alpha is equal to
  1. A.
    2+1\sqrt{2}+1
  2. B.
    2−1\sqrt{2}-1
  3. C.
    22+12\sqrt{2}+1
  4. D.
    22−12\sqrt{2}-1
Show answer

Correct option: A

[JEE Main 2019 · 9 April · Shift II]

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