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JEE Main 2019 · 8 Apr · Shift II

JEE Main 2019 Mathematics question on Matrices and Determinants

If the system of linear equations
x−2y+kz=1x - 2y + kz = 1, 2x+y+z=22x + y + z = 2, 3x−y−kz=33x - y - kz = 3
has a solution (x,y,z)(x, y, z), z≠0z \neq 0, then (x,y)(x, y) lies on the straight line whose equation is
  1. A.
    3x−4y−4=03x - 4y - 4 = 0
  2. B.
    3x−4y−1=03x - 4y - 1 = 0
  3. C.
    4x−3y−4=04x - 3y - 4 = 0
  4. D.
    4x−3y−1=04x - 3y - 1 = 0
Show answer

Correct option: C

[JEE Main 2019 · 8 Apr · Shift II]

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