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JEE Main 2019 · 9 April · Shift II

JEE Main 2019 Mathematics question on Matrices and Determinants

If the system of equations 2x+3y−z=02x + 3y - z = 0, x+ky−2z=0x + ky - 2z = 0 and 2x−y+z=02x - y + z = 0 has a non-trivial solution (x,y,z)(x, y, z), then xy+yz+zx+k\frac{x}{y} + \frac{y}{z} + \frac{z}{x} + k is equal to
  1. A.
    −4-4
  2. B.
    12\frac{1}{2}
  3. C.
    −14-\frac{1}{4}
  4. D.
    34\frac{3}{4}
Show answer

Correct option: B

[JEE Main 2019 · 9 April · Shift II]

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