If the sum of the first ten terms of the series (13/5 )^2 + (22/5 )^2 + (31/5 )^2 + 4^2 + (44/5 )^2 + … is 16/5m, then m is equal to

If the sum of the first ten terms of the series (13/5 )^2 +… — JEE Main 2016 Mathematics PYQ

JEE Main 2016

If the sum of the first ten terms of the series

\left(1\frac{3}{5}\right)^2 + \left(2\frac{2}{5}\right)^2 + \left(3\frac{1}{5}\right)^2 + 4^2 + \left(4\frac{4}{5}\right)^2 + \ldots

\frac{16}{5}m

, then

m

is equal to

Show answer

Correct option: B

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